3.314 \(\int \frac{1}{(-2+b x^2) \sqrt [4]{-1+b x^2}} \, dx\)

Optimal. Leaf size=77 \[ -\frac{\tan ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{2} \sqrt [4]{b x^2-1}}\right )}{2 \sqrt{2} \sqrt{b}}-\frac{\tanh ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{2} \sqrt [4]{b x^2-1}}\right )}{2 \sqrt{2} \sqrt{b}} \]

[Out]

-ArcTan[(Sqrt[b]*x)/(Sqrt[2]*(-1 + b*x^2)^(1/4))]/(2*Sqrt[2]*Sqrt[b]) - ArcTanh[(Sqrt[b]*x)/(Sqrt[2]*(-1 + b*x
^2)^(1/4))]/(2*Sqrt[2]*Sqrt[b])

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Rubi [A]  time = 0.013133, antiderivative size = 77, normalized size of antiderivative = 1., number of steps used = 1, number of rules used = 1, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.048, Rules used = {398} \[ -\frac{\tan ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{2} \sqrt [4]{b x^2-1}}\right )}{2 \sqrt{2} \sqrt{b}}-\frac{\tanh ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{2} \sqrt [4]{b x^2-1}}\right )}{2 \sqrt{2} \sqrt{b}} \]

Antiderivative was successfully verified.

[In]

Int[1/((-2 + b*x^2)*(-1 + b*x^2)^(1/4)),x]

[Out]

-ArcTan[(Sqrt[b]*x)/(Sqrt[2]*(-1 + b*x^2)^(1/4))]/(2*Sqrt[2]*Sqrt[b]) - ArcTanh[(Sqrt[b]*x)/(Sqrt[2]*(-1 + b*x
^2)^(1/4))]/(2*Sqrt[2]*Sqrt[b])

Rule 398

Int[1/(((a_) + (b_.)*(x_)^2)^(1/4)*((c_) + (d_.)*(x_)^2)), x_Symbol] :> With[{q = Rt[-(b^2/a), 4]}, Simp[(b*Ar
cTan[(q*x)/(Sqrt[2]*(a + b*x^2)^(1/4))])/(2*Sqrt[2]*a*d*q), x] + Simp[(b*ArcTanh[(q*x)/(Sqrt[2]*(a + b*x^2)^(1
/4))])/(2*Sqrt[2]*a*d*q), x]] /; FreeQ[{a, b, c, d}, x] && EqQ[b*c - 2*a*d, 0] && NegQ[b^2/a]

Rubi steps

\begin{align*} \int \frac{1}{\left (-2+b x^2\right ) \sqrt [4]{-1+b x^2}} \, dx &=-\frac{\tan ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{2} \sqrt [4]{-1+b x^2}}\right )}{2 \sqrt{2} \sqrt{b}}-\frac{\tanh ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{2} \sqrt [4]{-1+b x^2}}\right )}{2 \sqrt{2} \sqrt{b}}\\ \end{align*}

Mathematica [C]  time = 0.157584, size = 132, normalized size = 1.71 \[ \frac{6 x F_1\left (\frac{1}{2};\frac{1}{4},1;\frac{3}{2};b x^2,\frac{b x^2}{2}\right )}{\left (b x^2-2\right ) \sqrt [4]{b x^2-1} \left (b x^2 \left (2 F_1\left (\frac{3}{2};\frac{1}{4},2;\frac{5}{2};b x^2,\frac{b x^2}{2}\right )+F_1\left (\frac{3}{2};\frac{5}{4},1;\frac{5}{2};b x^2,\frac{b x^2}{2}\right )\right )+6 F_1\left (\frac{1}{2};\frac{1}{4},1;\frac{3}{2};b x^2,\frac{b x^2}{2}\right )\right )} \]

Warning: Unable to verify antiderivative.

[In]

Integrate[1/((-2 + b*x^2)*(-1 + b*x^2)^(1/4)),x]

[Out]

(6*x*AppellF1[1/2, 1/4, 1, 3/2, b*x^2, (b*x^2)/2])/((-2 + b*x^2)*(-1 + b*x^2)^(1/4)*(6*AppellF1[1/2, 1/4, 1, 3
/2, b*x^2, (b*x^2)/2] + b*x^2*(2*AppellF1[3/2, 1/4, 2, 5/2, b*x^2, (b*x^2)/2] + AppellF1[3/2, 5/4, 1, 5/2, b*x
^2, (b*x^2)/2])))

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Maple [F]  time = 0.039, size = 0, normalized size = 0. \begin{align*} \int{\frac{1}{b{x}^{2}-2}{\frac{1}{\sqrt [4]{b{x}^{2}-1}}}}\, dx \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(b*x^2-2)/(b*x^2-1)^(1/4),x)

[Out]

int(1/(b*x^2-2)/(b*x^2-1)^(1/4),x)

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Maxima [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{{\left (b x^{2} - 1\right )}^{\frac{1}{4}}{\left (b x^{2} - 2\right )}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(b*x^2-2)/(b*x^2-1)^(1/4),x, algorithm="maxima")

[Out]

integrate(1/((b*x^2 - 1)^(1/4)*(b*x^2 - 2)), x)

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Fricas [B]  time = 77.9659, size = 701, normalized size = 9.1 \begin{align*} \left [\frac{2 \, \sqrt{2} \sqrt{b} \arctan \left (\frac{\sqrt{2}{\left (b x^{2} - 1\right )}^{\frac{1}{4}}}{\sqrt{b} x}\right ) + \sqrt{2} \sqrt{b} \log \left (-\frac{b^{2} x^{4} - 2 \, \sqrt{2}{\left (b x^{2} - 1\right )}^{\frac{1}{4}} b^{\frac{3}{2}} x^{3} + 4 \, \sqrt{b x^{2} - 1} b x^{2} + 4 \, b x^{2} - 4 \, \sqrt{2}{\left (b x^{2} - 1\right )}^{\frac{3}{4}} \sqrt{b} x - 4}{b^{2} x^{4} - 4 \, b x^{2} + 4}\right )}{8 \, b}, \frac{2 \, \sqrt{2} \sqrt{-b} \arctan \left (\frac{\sqrt{2}{\left (b x^{2} - 1\right )}^{\frac{1}{4}} \sqrt{-b}}{b x}\right ) - \sqrt{2} \sqrt{-b} \log \left (-\frac{b^{2} x^{4} + 2 \, \sqrt{2}{\left (b x^{2} - 1\right )}^{\frac{1}{4}} \sqrt{-b} b x^{3} - 4 \, \sqrt{b x^{2} - 1} b x^{2} + 4 \, b x^{2} - 4 \, \sqrt{2}{\left (b x^{2} - 1\right )}^{\frac{3}{4}} \sqrt{-b} x - 4}{b^{2} x^{4} - 4 \, b x^{2} + 4}\right )}{8 \, b}\right ] \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(b*x^2-2)/(b*x^2-1)^(1/4),x, algorithm="fricas")

[Out]

[1/8*(2*sqrt(2)*sqrt(b)*arctan(sqrt(2)*(b*x^2 - 1)^(1/4)/(sqrt(b)*x)) + sqrt(2)*sqrt(b)*log(-(b^2*x^4 - 2*sqrt
(2)*(b*x^2 - 1)^(1/4)*b^(3/2)*x^3 + 4*sqrt(b*x^2 - 1)*b*x^2 + 4*b*x^2 - 4*sqrt(2)*(b*x^2 - 1)^(3/4)*sqrt(b)*x
- 4)/(b^2*x^4 - 4*b*x^2 + 4)))/b, 1/8*(2*sqrt(2)*sqrt(-b)*arctan(sqrt(2)*(b*x^2 - 1)^(1/4)*sqrt(-b)/(b*x)) - s
qrt(2)*sqrt(-b)*log(-(b^2*x^4 + 2*sqrt(2)*(b*x^2 - 1)^(1/4)*sqrt(-b)*b*x^3 - 4*sqrt(b*x^2 - 1)*b*x^2 + 4*b*x^2
- 4*sqrt(2)*(b*x^2 - 1)^(3/4)*sqrt(-b)*x - 4)/(b^2*x^4 - 4*b*x^2 + 4)))/b]

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Sympy [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{\left (b x^{2} - 2\right ) \sqrt [4]{b x^{2} - 1}}\, dx \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(b*x**2-2)/(b*x**2-1)**(1/4),x)

[Out]

Integral(1/((b*x**2 - 2)*(b*x**2 - 1)**(1/4)), x)

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Giac [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{{\left (b x^{2} - 1\right )}^{\frac{1}{4}}{\left (b x^{2} - 2\right )}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(b*x^2-2)/(b*x^2-1)^(1/4),x, algorithm="giac")

[Out]

integrate(1/((b*x^2 - 1)^(1/4)*(b*x^2 - 2)), x)